Ok options for scoring.
Simple doubling S(n + 1) = 2 * S(n)
0: 3 - 1
1: 4 - 2
2: 5 - 4
3: 6 - 8
4: 7 - 16
5: 8 - 32
6: 9 - 64
7: 10 - 128
.
.
.
22: 25 - 4194304
Advantage increment. S(n+1) = 2 * S(n) + (n + 1) - S(n-1)
0: 3 - 1
1: 4 - 3
2: 5 - 7
3: 6 - 14
4: 7 - 25
5: 8 - 41
6: 9 - 63
7: 10 - 92
.
.
.
22: 25 - 2047
The second method basically ensures that it is always better to get a longer word plus a shorter word than two middle words. For instance there is a 4 point benefit to getting a 7-letter word and a 5-letter word over 2 6-letter words. In the old system the benefit was always 1 in this system it is n+1
Daniel Wigton
npub1w4…q30zp
2026-10-13 15:06:56 UTC
in reply to nevent1q…sz70
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npub1w4jkwspqn9svwnlrw0nfg0u2yx4cj6yfmp53ya4xp7r24k7gly4qaq30zpSeen on
wss://theforest.nostr1.comPublished at
2026-10-13 15:06:56 UTCEvent JSON
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"content": "Ok options for scoring.\n\nSimple doubling S(n + 1) = 2 * S(n)\n0: 3 - 1\n1: 4 - 2\n2: 5 - 4\n3: 6 - 8\n4: 7 - 16\n5: 8 - 32\n6: 9 - 64\n7: 10 - 128\n.\n.\n.\n22: 25 - 4194304\n\nAdvantage increment. S(n+1) = 2 * S(n) + (n + 1) - S(n-1)\n\n0: 3 - 1\n1: 4 - 3\n2: 5 - 7\n3: 6 - 14\n4: 7 - 25\n5: 8 - 41\n6: 9 - 63\n7: 10 - 92\n.\n.\n.\n22: 25 - 2047\n\n\nThe second method basically ensures that it is always better to get a longer word plus a shorter word than two middle words. For instance there is a 4 point benefit to getting a 7-letter word and a 5-letter word over 2 6-letter words. In the old system the benefit was always 1 in this system it is n+1",
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