I couldn't resist some back of the envelope calculations.
Schwarszchield radius: \[r = \frac{2GM}{c^2}\]
Newton's gravitational acceleration:
\[a = \frac{GM}{r^2}\]
Acceleration at the horizon:
\[a = \frac{GMc^4}{4G^2M^2} = \frac{c^4}{4GM}\]
Just looking at orders of magniture: \(c = 10^8\), \(G-10^{-11}\), \(M = 10^{41}\) gives the approximation \(a=10^2\), which is close enough.
Bartosz Milewski
npub1gl…xtqzy
2026-08-25 18:57:48 UTC
in reply to nevent1q…tdt9
Author Public Key
npub1glgxnwfzwxpvj3l6d96vxttum7rkfav3dmcwdkyqz9eqkt83mdfsaxtqzySeen on
wss://relay.momostr.pinkPublished at
2026-08-25 18:57:48 UTCEvent JSON
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